(10+x^2)=144

Solution for (10+x^2)=144 equation:

(10+x^2)=144

We move all terms to the left:

(10+x^2)-(144)=0

We get rid of parentheses

x^2+10-144=0

We add all the numbers together, and all the variables

x^2-134=0

a = 1; b = 0; c = -134;
Δ = b2-4ac
Δ = 02-4·1·(-134)
Δ = 536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{536}=\sqrt{4*134}=\sqrt{4}*\sqrt{134}=2\sqrt{134}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{134}}{2*1}=\frac{0-2\sqrt{134}}{2}
=-\frac{2\sqrt{134}}{2}
=-\sqrt{134}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{134}}{2*1}=\frac{0+2\sqrt{134}}{2}
=\frac{2\sqrt{134}}{2}
=\sqrt{134}
$